2[-4(2x+3)+4(3x-4)]=

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Solution for 2[-4(2x+3)+4(3x-4)]= equation:


Simplifying
2[-4(2x + 3) + 4(3x + -4)] = 0

Reorder the terms:
2[-4(3 + 2x) + 4(3x + -4)] = 0
2[(3 * -4 + 2x * -4) + 4(3x + -4)] = 0
2[(-12 + -8x) + 4(3x + -4)] = 0

Reorder the terms:
2[-12 + -8x + 4(-4 + 3x)] = 0
2[-12 + -8x + (-4 * 4 + 3x * 4)] = 0
2[-12 + -8x + (-16 + 12x)] = 0

Reorder the terms:
2[-12 + -16 + -8x + 12x] = 0

Combine like terms: -12 + -16 = -28
2[-28 + -8x + 12x] = 0

Combine like terms: -8x + 12x = 4x
2[-28 + 4x] = 0
[-28 * 2 + 4x * 2] = 0
[-56 + 8x] = 0

Solving
-56 + 8x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '56' to each side of the equation.
-56 + 56 + 8x = 0 + 56

Combine like terms: -56 + 56 = 0
0 + 8x = 0 + 56
8x = 0 + 56

Combine like terms: 0 + 56 = 56
8x = 56

Divide each side by '8'.
x = 7

Simplifying
x = 7

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